IB CHEMISTRY · PAPER 1B
IB Chemistry Paper 1B: Graphs and Experimental Data in Five Steps
Separate observation, numerical evidence, chemical explanation, conclusion and limitation when a graph or data table is unfamiliar.
- Syllabus
- IB Chemistry · first assessment 2025
- Relevant to
- SL · HL
In this guide
An unfamiliar Paper 1B graph does not mean you must invent unfamiliar Chemistry. The task usually asks what conclusion can responsibly be drawn from the evidence provided.
Order matters. If you begin by recalling everything you know about the topic, you may impose an expected story on the data. Record what the axes, units, values and conditions actually show first; introduce the chemical model afterwards.
The five-step order
From evidence to conclusion in five steps
- 1Axes and units
- 2Trend
- 3Numerical comparison
- 4Chemical explanationData are not the explanation
- 5Conclusion and limitation
1. Read the axes, units and conditions
Do not stop at “concentration” and “rate”. Identify the independent variable, its unit, the exact dependent quantity and the measured range. Initial rate is not the same as total reaction time, and the unit determines how you can cite the evidence.
2. Describe the observable trend
State direction and pattern without yet supplying a cause: increasing, decreasing, approximately linear, curved, levelling or containing an anomalous point. “Positive correlation” may be less precise than the graph permits.
3. Quantify at least one comparison
Choose two relevant points. State the direction and size of the change, using a ratio or difference where useful. Numerical evidence demonstrates that your conclusion came from this dataset rather than a memorised statement.
4. Connect an appropriate chemical explanation
Now select the model that interprets the pattern: collision theory, particle distribution, equilibrium, bonding or a structure–property relationship, for example. The model must explain the evidence rather than replace it.
5. State the conclusion and its limit
Answer the investigation question without claiming more than the evidence supports. Four points across a defined range do not establish a law for every concentration, and a correlation alone does not eliminate every alternative variable.
Original exam-style data example
Concentration and initial rate
Initial rate / cm3 s−1
Concentration / mol dm−3
| Concentration / mol dm−3 | Initial rate / cm3 s−1 |
|---|---|
| 0.10 | 0.42 |
| 0.20 | 0.81 |
| 0.30 | 1.25 |
| 0.40 | 1.62 |
The cm3 s−1 quantity is the initial gradient of gas volume against time at fixed temperature and pressure, not automatically a molar concentration change per second. The dashed line is a visual guide, not a statistically established model.
- Initial answer
- “A higher concentration causes a faster reaction.”
- What is missing?
- It gives no numerical evidence, comparison or limit to the claim.
- Improved answer
- “When concentration increased from 0.10 to 0.40 mol dm−3, initial rate increased from 0.42 to 1.62 cm3 s−1. Rate changed by approximately a factor of four while concentration increased by a factor of four, so the data support an approximately directly proportional relationship over this range. A higher particle concentration allows more successful collisions per unit time. The dataset does not show whether the same relationship continues outside the measured range.”
- Why it works
- It starts from data, makes a numerical comparison and confines the chemical interpretation to the measured range.
A second example: absorbance with repeats
Absorbance: look inside the repeats
Original synthetic teaching data, not laboratory results or an official IB task. They model readings for a stable, clear solution at fixed wavelength and cuvette path length. Absorbance is dimensionless.
Dependent quantity: absorbance, A (dimensionless)
Concentration / mmol dm⁻³
○ repeated reading · △ reading to investigate. No fitted line or confidence band is shown.
| Concentration / mmol dm⁻³ | A1 | A2 | A3 |
|---|---|---|---|
| 0.00 | 0.003 | 0.005 | 0.004 |
| 0.02 | 0.158 | 0.162 | 0.160 |
| 0.04 | 0.318 | 0.325 | 0.322 |
| 0.06 | 0.482 | 0.820 △ | 0.488 |
| 0.08 | 0.635 | 0.644 | 0.641 |
Your task: describe the pattern using numbers, identify the reading that needs investigation, explain whether it can be excluded, and write a defensible conclusion.
Apply the same five steps:
- Axes, units and conditions. Concentration is in mmol dm−3; absorbance A is dimensionless. Wavelength, path length, chemical form of the absorber and solution conditions must be comparable. Each level has three readings, including a zero-concentration blank.
- Observable trend. Absorbance generally increases with concentration. The 0.820 reading at 0.06 mmol dm−3 sits far above its repeats, 0.482 and 0.488; a single mean would conceal that discrepancy.
- Numerical comparison. The mean at 0.02 is 0.160; at 0.04 it is about 0.322, roughly twice as large. At 0.08 it is 0.640, four times the 0.02 mean. Including all three readings at 0.06 gives about 0.597, not the roughly 0.485 suggested by the other two readings alone. The blank mean is 0.004, so do not force a line through an assumed exact zero.
- Chemical interpretation. Under suitable dilute-solution conditions, the Beer–Lambert model A = εlc predicts proportionality at fixed wavelength, optical path and chemical species. A dirty cuvette, a bubble, inconsistent blanking, preparation error or instrument problem could explain a discrepant reading; none has been demonstrated by this table. Check the raw record, inspect the cuvette and repeat the level under the same controls. Do not delete 0.820 merely to improve linearity; document any justified exclusion and retain the original record.
- Conclusion and limitation. “The repeat pattern broadly supports increasing absorbance with concentration across 0.00–0.08 mmol dm−3, with approximately proportional changes at the unflagged levels. The 0.06 level contains an unresolved inconsistent reading. These five synthetic levels do not establish the cause of that reading, a statistically certain calibration, or validity beyond this range.”
The raw repeats, not a conveniently smooth graph, determine which comparison can be defended. This is a worked article exercise; it is not a separately auto-marked bank question.
Observation, explanation, conclusion and limitation
A strong answer performs four distinguishable jobs.
- Observation: what do the values or graph show? It contains no assumed cause.
- Explanation: which chemical model interprets the trend? It does not replace numerical evidence.
- Conclusion: what investigation question is answered? It connects directly to the task.
- Limitation: what wider claim cannot be made? It controls the strength of certainty.
Anatomy of a strong answer
0.10 to 0.40 mol dm−3; 0.42 to 1.62 cm3 s−1
Both quantities increased by approximately a factor of four.
A higher particle concentration can produce more successful collisions per unit time.
The claim applies only to the measured range.
During practice, label each sentence “data”, “relationship”, “explanation” or “limit”. A missing label tells you exactly what to add. This is a training device, not a required examination format.
Five common errors
- No unit. A number without its unit does not fully identify the quantity.
- No numerical comparison. “It increases” does not show the magnitude of the trend.
- Explanation precedes description. The response becomes a generic content statement.
- One point becomes a general rule. A relationship must be defended from a pattern.
- Correlation automatically becomes causation. A causal claim must also consider controls and design.
In correction, identify the first missing step rather than only editing the final sentence. If the axis was misread, a sophisticated explanation built afterwards cannot rescue the answer.
A fifteen-minute weekly practice block
Choose one graph and one short table each week. Spend five minutes marking axes, units and conditions. Spend five minutes writing one quantified observation, one chemical explanation and one limitation. Use the last five minutes to inspect feedback, close it and rewrite.
Change the context from week to week. After rates, use energetic, equilibrium, spectroscopy or titration data. The analytical frame stays stable while the chemical model changes.
Paper 1B fits inside the wider IB Chemistry exam-preparation system, where targeted data work moves into mixed practice and eventually timed simulation. If you cannot tell why a mark is missing, use the six-error diagnosis and choose practice for the first absent step.
Practise interpreting unfamiliar data
Apply the five-step method to both worked examples above. A dedicated standalone IB data-analysis set is not yet published.
Related guides
Exam preparation
IB Chemistry Exam Preparation: Paper 1A, Paper 1B and Paper 2
Use past papers purposefully: choose a priority, analyse mistakes and check what you have learned.
Read the guide →Scientific Investigation / IA
IB Chemistry IA / Scientific Investigation: From Question to Evaluation
Develop a clear Scientific Investigation from research question and method to analysis and evaluation.
Read the guide →Sources and further reading
Official examination and admissions sources
- IB Chemistry in the Diploma Programme (opens in a new tab)
- Official IB Chemistry Guide — first assessment 2025 (opens in a new tab)